弧长12.8米,弦长11.4米,求高度?

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弧长C=12.8米,弦长L=11.4米,求高度H?弧半径为R.Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*RnR0=7R1=7.605R2=7.759R3=7.767R4=7.767R=7.767米H=R-(R^2-(L/2)^2)^0.5=7.767-(7.767^2-(11.4/2)^2)^0.5=2.49...