(1)答案:电流的热效应;S2闭合时是高温档
(2)R1=U平方/P=220平方/1100W=44欧
Q=Pt=1100W.乘3乘60S=198000J
(3)R=U平方/P=220平方/1000W=48.4欧
取下R2,与R1串联一只4.4欧的电阻
(1)答案:电流的热效应;S2闭合时是高温档
(2)R1=U平方/P=220平方/1100W=44欧
Q=Pt=1100W.乘3乘60S=198000J
(3)R=U平方/P=220平方/1000W=48.4欧
取下R2,与R1串联一只4.4欧的电阻