2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
=(3-1)(3+1)(3^2+1)(3^4+1).(3^32+1)+1 关键是:把2变成3-1
=(3^2-1)(3^2+1)(3^4+1).(3^32+1)+1能后多次运用平方差公式
=(3^4-1)(3^4+1).(3^32+1)+1
=...
=(3^32-1)(3^32+1)+1
=3^64-1+1
=3^64
= 3.4336838202925 * 10^30
计算：2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
2个回答
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