Question

1,已知向量a是以点（3,-1）为起点,且与向量b=（-3,4）垂直的单位向量,求向量a的终点坐标.

Answer 1

1.（X-3）^2+(Y+1)^2=1

-3(X-3)+4(Y+1)=0

得X=19/5 Y=-2/5

2.