Question

若实数x,y满足（1+i)x+(1-i)y=2,求x*y的值.

Answer 1

(1+i)x+(1-i)y=2

x+y+i*(x-y)=2

从而有

x+y=2

x-y=0

联立解得

x=y=1

所以x*y=1