答：
y=[log2(x)]²-log2(4x)
=[log2(x)]²-log2(x)-log2(4)
=[log2(x)-1/2]²-9/4
>=-9/4
所以：y的值域为（-9/4,+∞)
y=log2(x²)-log2(4x)
=log2(x²)-log2(x)-log2(4)
=log2(x²/x)-2
=log2(x)-2
所以：y的值域为（-∞,+∞)
y=(log2 (x)^2-log2(4x)
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