(1)①∵∠AGB=∠HGC ∠BAC=∠GHC=90°∴∠ABG=∠ACF且AB=AC∴△BAG≌△ACF∴BG=CF②易证△CBH≌△FBH∴CH=FH∴BG=CF=2CH(2) 过G作GM⊥BC,交BC于M设BM=X在△BGM中 ∵∠GBM=30°∴BG=2X,BM=√3X∵∠GCM=45° ∠GMC=9...
(1)①∵∠AGB=∠HGC ∠BAC=∠GHC=90°∴∠ABG=∠ACF且AB=AC∴△BAG≌△ACF∴BG=CF②易证△CBH≌△FBH∴CH=FH∴BG=CF=2CH(2) 过G作GM⊥BC,交BC于M设BM=X在△BGM中 ∵∠GBM=30°∴BG=2X,BM=√3X∵∠GCM=45° ∠GMC=9...