(1)若(a+b)垂直(a-b);
(a+b)(a-b)
=a²-b²
=(1+4)-|b|²
=0;
|b|=√5;
(2)设C(x,y)则有:
x/1=y/2;
y=2x;
|c|=√(x²+y²)=√(4x²+x²)=3√5;
∴5x²=45;
x²=9;
x=±3;
所以C(3,6)或(-3,-6)
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(1)若(a+b)垂直(a-b);
(a+b)(a-b)
=a²-b²
=(1+4)-|b|²
=0;
|b|=√5;
(2)设C(x,y)则有:
x/1=y/2;
y=2x;
|c|=√(x²+y²)=√(4x²+x²)=3√5;
∴5x²=45;
x²=9;
x=±3;
所以C(3,6)或(-3,-6)
很高兴为您解答,skyhunter002为您答疑解惑
如果本题有什么不明白可以追问,