(1)由题意,这名选手距目标xm处的命中率 P x =
k
x 2 ,∵ P 100 =
1
2 ,∴k=5000.
故 P 150 =
5000
15 0 2 =
2
9 , P 200 =
5000
20 0 2 =
1
8 .
即这名射手在150m处、200m处的命中率分别为
2
9 ,
1
8 .(6分)
(2)记100m,150m,200m处命中目标分别为事件A,B,C,
由(1)知P=P(A +
.
A •B+
.
A •
.
B •C )=
1
2 +
1
2 ×
2
9 +
1
2 ×
7
9 ×
1
8 =
95
144 .(12分)