x²-10x+y²-2y+26=0
(x-5)²=x²-10x+25
(x-5)(x-5)=x²-10x+25
(x-5)²+(y-1)²=0
x-5=0 y-1=0
x=5 y=1
求根号下x²y²=25
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
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