设原来甲种矿石x吨,乙种矿石y吨.
54%x+36%y=﹙x+y﹚×48%……………………………………………………①
54%﹙x-12﹚+36%﹙y+10﹚=﹙x-12+y+10﹚×45%……………………②
①两边同时除以6%得:9x+6y=8﹙x+y﹚
9x-8x=8y-6y
x=2y
②两边同时除以9%得:6﹙x-12﹚+4﹙y+10﹚=5﹙x+y-2﹚
6x+4y-32=5x+5y-10
x-y=22
将x=2y代入得:2y-y=22
y=22
x=2y=2×22=44
∴ x=44
y=22