Question

求lgx=lga+lgb,log根号3x=-2/3,lnx=3lnn+lnm,

Answer 1

lgx=lga+lgb

lgx=lgab

x=ab

log根号3x=-2/3,

log√3(x)=-2/3

x=(√3)^(-2/3)

x=3^(1/2*-2/3)

x=3^(-1/3)

x=1/3√3(x的开3次方分之一)

lnx=3lnn+lnm

lnx=3lnn+lnm

lnx=lnn^3*m

x=mn^3