若logx^【2^(1/2)+1】=-1,则x=?
1个回答
x^(-1) = 2^(1/2)+1
=>
x = 1/(2^(1/2)+1)
=(2^(1/2)-1) / (2^(1/2)+1)*(2^(1/2) - 1)
=2^(1/2)- 1
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