Question

用高斯函数计算函数值域f（x）=(2的x次方)/(2的x次方+1) -1/2,则函数y=[f(x)]+[f(-x)]的值

Answer 1

当x＜0时

[f(x)]=-1,[f(-x)]=0,所以y=[f(x)]+[f(-x)]=-1

当x=0时

[f(x)]=0,[f(-x)]=0,所以y=[f(x)]+[f(-x)]=0

当x＞0时

[f(x)]=0,[f(-x)]=-1,所以y=[f(x)]+[f(-x)]=-1

所以值域是{0,-1}