Question

一质量为250g,加热到580℃,降低到20℃,若把放出的热量给30℃.0.5kg的水加热,水温可升高多少度?

Answer 1

Q放=cm(t0-t)=0.46×10ˆ3J/(kg.℃)*0.25kg*(580℃-20℃)=6.44×10ˆ4JQ吸=Q放=c水m水(t水-t0水)得t水-t0水=Q吸/c水m水=6.44×10ˆ4J/[4.2×10ˆ3J/(kg.℃)*0.5kg]=30.7℃水温可升高30.7℃...