已知1/1×3=1/2(1-1/3),1/3×5=1/2(1/3-1/5),1/5×7=1/2(
1个回答
1.1/2(1/2001-1/2003)
2.=1/2(1-1/3+1/3-1/5+……+1/2001-1/2003)
=1/2(1-1/2003)
=1001/2003
相关问题
1/1×3+1/3×5+1/5×7+.+1/99×101=(2/1×3+2/3×5+2/5×7+.+2/99×
已知1/2×3=1/2-1/3,计算:1+1/2×3+1/3×4+1/4×5+1/5×6
已知:2/1×3=1/1-1/3,求①2/1×3+2/3×5+2/5×7+2/7×9+2/9×11的值;
先阅读,1\1×3=1\2(1-1\3),1\3×5=1\2(1\3-1\5),1\5×7=1\2(1\5-1\7)
观察算式:1+3= (1+3)×2 2 ,1+3+5= (1+5)×3 2 ,1+3+5+7= (1+7)×4 2 …
已知数列[1/1×3],[1/1×5],[1/5×7],[1/7×9],…[1(2n−1)×(2n+1)
1/1×3+1/3×5+1/5×7+···+1/(2n-1)(2n+1)
1.求和1/(1×3)+1/(3×5)+1/(5×7)…1/(2n-1)(2n-2)
观察式子:[1/1×3]=[1/2](1-[1/3]),[1/3×5]=[1/2]([1/3]-[1/5]),[1/5×
(1+1/2)×(1-1/3)=3/2×2/3=1×(1+1/2)×(1+1/4)×(1-1/3)×(1-1/5)=3/