Question

如图一,△ABC是锐角三角形,高BD、CE相交于点H,找出角BHC和∠A之间存在何种等量关系

Answer 1

∠BHC

=∠BDC+∠ECA

=90°+∠ECA

=90°+(90°-∠A)

=180°-∠A

∴∠BHC+∠A=180°,它们互补