Question

分解因式 xy〈x-y〉-x〈x-y〉的2次方

Answer 1

xy〈x-y〉-x〈x-y〉的2次方

=xy(x-y)-(x^2-xy)(x-y)

=(xy-x^2+xy)(x-y)

=(2xy-x^2)(x-y)

=x(2y-x)(x-y)