两边同时除以a,得
a-3+1/a=0
a+1/a=3
先求
(a^6+1)/a^3
=a^3+1/a^3
=(a+1/a)(a^2-1+1/a^2)
=3×[(a+1/a)^2-3]
=3×(3^2-3)
=3×6
=18
所以a^3/(a^6+1)=1/18.
两边同时除以a,得
a-3+1/a=0
a+1/a=3
先求
(a^6+1)/a^3
=a^3+1/a^3
=(a+1/a)(a^2-1+1/a^2)
=3×[(a+1/a)^2-3]
=3×(3^2-3)
=3×6
=18
所以a^3/(a^6+1)=1/18.