Question

二次根式的混合运算4个计算题,要过程,最好有图,谢谢啦⊙▽⊙.

Answer 1

6. (a-b)^2+(b-c)^2+(c-a)^2=2*[a^2+b^2+c^2-ab-bc-ca]答案=0.5*((a-b)^2+(b-c)^2+(c-a)^2)=0.5*( (2+sqrt(3))^2+(2-sqrt(3))^2+4^2)=159.由於绝对值与根号必为正 故|a+1|=0 sqrt(2b-4)=0 a=-1;b=2(-1+2)^2010= 11...