由已知条件得:|AB-BC| = 20-18 = 2,△ABC周长 = 20+18 = 38 ;
所以,BC = AB±2 .
且 AB=AC ,可得:
△ABC周长 = AB+AC+BC = 3AB±2 = 38 ;
可得:AB=AC=12、BC=15 或 AB=AC=40/3 、BC= 38 - 80/3 = 34/3
由已知条件得:|AB-BC| = 20-18 = 2,△ABC周长 = 20+18 = 38 ;
所以,BC = AB±2 .
且 AB=AC ,可得:
△ABC周长 = AB+AC+BC = 3AB±2 = 38 ;
可得:AB=AC=12、BC=15 或 AB=AC=40/3 、BC= 38 - 80/3 = 34/3