Question

数字中定义一种新运算为 X&Y=(X+1)(Y-2) (1)计算:-2&2 (2)若X&5=12,求X的值 &这个符号

Answer 1

(-2)&2

= (-2 + 1)×(2 - 2)

= (-1)×0

= 0

x&5 = 12

(x + 1)×(5 - 2) = 12

3(x + 1) = 12

x + 1 = 12÷3

x + 1 = 4

x = 4 - 1

x = 3