你做不出来!((1+cos20)/2sin20)-sin10(cot5-tan5)=?

1个回答

  • ((1+cos20°)/2sin20°)-sin10°(cot5°-tan5°)

    =((1+cos20°)/4sin10°cos10°)-sin10°(cot5°-tan5°)

    =(2cos10°/4sin10°)-2sin5°cos5°(cot5°-tan5°)

    =(cos10°/2sin10°)-2((cos5°)^2-(sin5°)^2)

    =(cos10°/2sin10°)-2cos10°

    =(cos10°-4sin10°cos10°)/2sin10°

    =(sin80°-2sin20°)/2sin10°

    =((sin80°-sin20°)-sin20°)/2sin10°

    =(2cos50°sin30°-sin20°)/2sin10°

    =(sin40°-sin20°)/2sin10°

    =2cos30°sin10°/2sin10°

    =cos30°

    =(根号3)/2