x→2(X^2-5X+6)/(X^2-6X+8)
1个回答
原式=(x-2)(x-3)/(x-2)(x-4)=(x-3)/(x-4)
所以极限=(2-3)/(2-4)=1/2
相关问题
5x/(x2+x-6)+(2x-5/x2-x-12)=7x-10/x2-6x+8
因式分解:(1)x^2-7x+6(2)x^2-5x+6(3)x^2-5x-6(4)x^2-7x+8(5)x^2-7x+1
x^2+8x+13/x^2+8x+15-x^2+5x+4/x^2+5x+6
1)2x+8=16 (2)x/5=10 (3)x+7x=8 (4)9x-3x=6 (5)6x-8=4 (6)5x+x=9
解方程:x-0.1x=0.634.4x=5.6=5.6=10=2.4x 2x除8+3x除6=6 8.8-5(x-0.2)
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
化简分式:5xx2+x−6+2x−5x2−x−12−7x−10x2−6x+8
化简分式:5xx2+x−6+2x−5x2−x−12−7x−10x2−6x+8
化简分式:5xx2+x−6+2x−5x2−x−12−7x−10x2−6x+8