解题思路:(1)先将分式通分,再按同分母的分式相加减的法则进行计算即可;
(2)先算括号里面的,再进行分式的约分即可.
(1)[1/x−3+
6
9−x2−
x−1
6−2x];
=
2(x+3)
2(x2−9)-[12
2(x2−9)+
(x−1)(x+3)
2(x2−9),
=
2x+6−12+x2+3x−x−3
2(x2−9),
=
x2+4x−9
2(x2−9);
(2)(
x+2y/x+y−
x
y)÷(
x
y+2−
x
x−y),
=
y(x+2y)−x(x+y)
y(x+y)]÷
x(x−y)+2y(x−y)−xy
y(x−y),
=
2y2−x2
y(x+y)•
y(x−y)
x2−2y2,
=-[x−y/x+y].
点评:
本题考点: 分式的混合运算.
考点点评: 本题是计算题,比较简单,考查了分式的混合运算,要注意运算顺序.