Question

数列的通项公式为an=sin 4/nπ 写出数列的前5项

Answer 1

n=1 a1=sin π/4=√2/2

n=2 a2=sin 2π/4=sinπ/2=1

n=3 a3=sin 3π/4=√2/2

n=4 a4=sin 4π/4=sinπ=-1

n=5 a3=sin 5π/4=-√2/2