Question

y=xarcsin(x/2)+根号(4-x平方),求导数,麻烦写详细点,

Answer 1

y=xarcsin(x/2)+√(4-x^2),

y'=[xarcsin(x/2)]'+[√(4-x^2)]',

=arcsin(x/2)+x*1/2*1/√(1-x^2/4)+1/2*(-2x)*1/√(4-x^2),

=arcsin(x/2)+x/√(4-x^2)-x/√(4-x^2),

=arcsin(x/2)

解毕