Question

y=3次根下x^2/(4次根下x^3) 求导

Answer 1

y=(3「x^2)/(4「x^3)=x^(2/3-3/4)=x^(-1/12)y'=-x^(-13/12)/12

y=3「（x^2/(4「x^3)）=(x^(2-3/4))^(1/3)=x^(5/12)y'=(5/12)x^(-7/12)