f(π/6)=f(π/3)
则有w*π/6+π/3+w*π/3+π/3=π+2kπ(k为整数)
或者w*π/3+π/3=w*π/6+π/3+2kπ(k为整数)
fx在(π/6,π/3)上有最小值,无最大值 周期T=2π/w≥2*(π/3-π/6)=π/3 w≤6
只有w*π/6+π/3+w*π/3+π/3=π+2kπ成立 解得 w=2/3+4k 说明k只能为0,1
将w代入f(x),必有π/6
f(π/6)=f(π/3)
则有w*π/6+π/3+w*π/3+π/3=π+2kπ(k为整数)
或者w*π/3+π/3=w*π/6+π/3+2kπ(k为整数)
fx在(π/6,π/3)上有最小值,无最大值 周期T=2π/w≥2*(π/3-π/6)=π/3 w≤6
只有w*π/6+π/3+w*π/3+π/3=π+2kπ成立 解得 w=2/3+4k 说明k只能为0,1
将w代入f(x),必有π/6