Question

已知x=根号3+1,求根号1-2x+x的平方分之x的平方的值

Answer 1

因为x=√3+1

所以x﹥0,x-1﹥0

原式=√[x²/(1-2x+x²)]

=√[x²/(x-1)²]

=x/(x-1)

=(√3+1)/(√3+1-1)

=(√3+1)/(√3)

=[(√3+1)×√3]/(√3×√3)

=(3+√3)/3