ABC
3B=A+C----->C=3B-A -------C
作为数列,则a1=A,a2=B
a3=3a2 -a1
an =3an-1 -an-2
假设an -kan-1 =(3-k)[an-1 -(an-2)/(3-k)]
令k =1/(3-k) k^2-3k+1 =0 (k-3/2)^2 =5/4 k=(3+根号5)/2
则an-kan-1是等比数列
.
ABC
3B=A+C----->C=3B-A -------C
作为数列,则a1=A,a2=B
a3=3a2 -a1
an =3an-1 -an-2
假设an -kan-1 =(3-k)[an-1 -(an-2)/(3-k)]
令k =1/(3-k) k^2-3k+1 =0 (k-3/2)^2 =5/4 k=(3+根号5)/2
则an-kan-1是等比数列
.