Question

求方程4X＾2-4XY-3Y＾2-5＝0的整数解．

Answer 1

(2x+y)(2x-3y)=5

2x+y=1,2x-3y=5 or

2x+y=5,2x-3y=1 or

2x+y=-1,2x-3y=-5 or

2x+y=-5,2x-3y=-1

得x=1,y=-1 or

x=2,y=1 or

x=-1,y=1 or

x=-2,y=-1