(1)十字相乘:(x-7)(x+2)=0,所以:x1=7,x2=-2;
(2)移项,(2y-1)^2-3(2y-1)=0,(2y-1)(2y-4)=0,即(2y-1)(y-2)=0
所以:y1=1/2,y2=2
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