5ax²+15x-2ax-6+2=6x²+4x-3ax-2a
(5a-6)x²+(11+a)x+(2a-4)=0
x1+x2=-(11+a)/(5a-6)
x1x2=(2a-4)/(5a-6)
x1=0
所以x1x2=0
(2a-4)/(5a-6)=0
所以a=2
x1+x2=-(11+a)/(5a-6)=-13/4
x1=0
所以x2=-13/4
5ax²+15x-2ax-6+2=6x²+4x-3ax-2a
(5a-6)x²+(11+a)x+(2a-4)=0
x1+x2=-(11+a)/(5a-6)
x1x2=(2a-4)/(5a-6)
x1=0
所以x1x2=0
(2a-4)/(5a-6)=0
所以a=2
x1+x2=-(11+a)/(5a-6)=-13/4
x1=0
所以x2=-13/4