Question

2+1)(2乘2+1)(4个2相乘+1)(8个2相乘+1)怎么样算简便

Answer 1

(2+1)(2乘2+1)(4个2相乘+1)(8个2相乘+1)

=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)

=(2^2-1)(2^2+1)(2^4+1)(2^8+1)

=(2^4-1)(2^4+1)(2^8+1)

=(2^8-1)(2^8+1)

=2^16-1

=65536-1

=65535