Question

已知分式方程(x+3)/(x-2)²＝A/(x-2)+B/(x-2)²,求A,B的值

Answer 1

两边乘以(x-2)²得

x+3=A(x-2)+B

=AX+(B-2A)

∴A=1

b-2A=3

∴A=1

B=5