∫(π/3→5π/6)cos(x+π/3)dx=∫(π/3→5π/6)cos(x+π/3)d(x+π/3)=[sin(x+π/3)+C]π/3→5π/6=sin(5π/6+π/3)-sin(π/3+π/3)=-(1/2+√3/2)
求定积分!∫(π/3→5π/6)(cos(x+π/3)dx
∫(π/3→5π/6)cos(x+π/3)dx=∫(π/3→5π/6)cos(x+π/3)d(x+π/3)=[sin(x+π/3)+C]π/3→5π/6=sin(5π/6+π/3)-sin(π/3+π/3)=-(1/2+√3/2)