填空:丙 0.2 (129+20-148.8=0.2)
计算:Zn + 2HCl ==== ZnCl2 + H2↑
65 2×36.5 2
m m1 0.2g
m=6.5g m1=7.3g
6.5/20 ×100%=32.5%
7.3/73 ×100%=10%
答:黄铜样品中锌的质量分数是32.5%,所用稀盐酸的质量分数是10%
填空:丙 0.2 (129+20-148.8=0.2)
计算:Zn + 2HCl ==== ZnCl2 + H2↑
65 2×36.5 2
m m1 0.2g
m=6.5g m1=7.3g
6.5/20 ×100%=32.5%
7.3/73 ×100%=10%
答:黄铜样品中锌的质量分数是32.5%,所用稀盐酸的质量分数是10%