Question

已知(-a)的-3次=-27,b的平方=10的-18次方,求a次根号b

Answer 1

(-a)^(-3) = -27

1/a^3 =27,a^3 =1/27,a＝1/3

b^2 = 10^(-18)=[10^(-9)]^2

b=10^(-9)

b^(1/a) =[10^(-9)]^(1/ 1/3)

=[10^(-9)]^3

=10^(-27)

=1/10^27