Question

已知(a+1)^2+|b-2|=0,求多项式a^2+3ab-7a^2b^2-2ab+1+5a^2b^2的值

Answer 1

已知(a+1)^2+|b-2|=0,

a+1=0;

a=-1;

b-2=0;

b=2;

求多项式a^2+3ab-7a^2b^2-2ab+1+5a^2b^2的值

=a²+ab-2a²b²+1

=(-1)²+(-1)×2-2×(-1)²×2²+1

=1-2-8+1

=-8;

很高兴为您解答,skyhunter002为您答疑解惑

如果本题有什么不明白可以追问,