(1)缺图
(2)根据题意可知ABCD是等腰梯形,∠DAB=∠ADC,∠ABC=∠DCB
由PA=PD,得∠DAP=∠ADP
又∠EAB=∠DAB-∠DAP,∠FDC=∠ADC-∠ADP,故∠EAB=∠FDC
又AB=DC,所以△ABE全等△DCF(ASA)
(1)缺图
(2)根据题意可知ABCD是等腰梯形,∠DAB=∠ADC,∠ABC=∠DCB
由PA=PD,得∠DAP=∠ADP
又∠EAB=∠DAB-∠DAP,∠FDC=∠ADC-∠ADP,故∠EAB=∠FDC
又AB=DC,所以△ABE全等△DCF(ASA)