因为ab/(a+b)=1/3
所以(a+b)/ab=3
即1/b+1/a=3 (1)
同理
1/b+1/c=4 (2)
1/a+1/c=5 (3)
(1)+(2)+(3)得
2(1/a+1/b+1/c)=12
即1/a+1/b+1/c=6 (4)
(4)-(1)得1/c=3 c=1/3
(4)-(2)得 1/a=2 a=1/2
(4)-(3)得 1/b=1 b=1
于是ab/(a+b+c)=(1/3)/(1/3+1/2+1)=2/11
因为ab/(a+b)=1/3
所以(a+b)/ab=3
即1/b+1/a=3 (1)
同理
1/b+1/c=4 (2)
1/a+1/c=5 (3)
(1)+(2)+(3)得
2(1/a+1/b+1/c)=12
即1/a+1/b+1/c=6 (4)
(4)-(1)得1/c=3 c=1/3
(4)-(2)得 1/a=2 a=1/2
(4)-(3)得 1/b=1 b=1
于是ab/(a+b+c)=(1/3)/(1/3+1/2+1)=2/11