Question

三角形ABD和三角形ACE是等腰三角形,∠BAD与∠CAE是直角.求证:BE=CD且BE⊥CD

Answer 1

1、∵△ABD和△ACE是等腰三角形∴AD=AB,AE=AC∵∠BAD=∠CAE∴∠BAD+∠BAC=∠BAC+∠CAE即∠DAC=∠BAE∴△ACD≌△ABE∴BE=CD2、设AC和BE交于M∵△ACD≌△ABE∴∠AEB=∠ACD即∠AEM=∠MCF∵∠AME=∠FMC∴△AME∽△CFM∴...