Question

如图,长方形ABCD中,AB=2根号3 cm,BC=4根号3 cm,点p以根号3 cm/s的速度在长方形的边上从A点出发

Answer 1

当t=2'‘时,

AP=t*√3

=2√3(cm)

∴△ABP以AP为底的高是AB=2√3

∴S△ABP=AP*AB2

=2√3*2√3/2

=6(cm^2)

当t=5''时,

AP=t*√3

=5√3(cm)

又长方形ABCD中,AB=2√3cm,BC=4√3,

∴AD=4√3

AP=5√3＞AD=4√3,

∴P点在CD上,且：DP=AP-AD

=5√3-4√3

=√3

∴CP=CD-DP

＝2√3-√3

=√3

∴S△BCP=BC*CP/2

=4√3*√3/2

=6(cm^2)