Question

A、B、C属于集合X,A的概率是0.4,B的概率是0.3,C的概率是0.25,A、B相互独立、A、C相互排斥,求A、C的

Answer 1

P(AUC)=P(A)+P(C)-P(A交C)=0.4+0.250=0.65

P(AUB)=P(A)+P(B)-P(A交B)=0.4+0.3-0.4×0.3=0.58

P(BUC)=P(B)+P(C)-P(B交C)=0.3+0.25-P(B交(X-A))

=0.55-[P(B交X)-P(B交A)]=0.55-[0.3-0.3×0.4]=0.37