(3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f
对任意的实数x均成立
令x=0,则
(3*0+1)^5=f
∴f=1
若(3x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,求f的值
2个回答
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