[(1+2^-(1/32)]*[(1+2^-(1/

1个回答

[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]
=[(1-2^-(1/32)]*[(1+2^-(1/32)]*[(1+2^-(1/16)]*[(1+2^-(1/8)]*[(1+2^-(1/4)]*[(1+2^-(1/2)]/[(1-2^-(1/32)]
=[1-2^(-1)]/[(1-2^-(1/32)]
=1/[(2-2^(31/32)]

(2+1)(2²+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1=
(2^2+1)*(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1）
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
(2+1)(2^2+1)(2^4+1)(2^8+1)（2^16+1）－2^32
（1+2^(1/32))*(1+2^(1/16))*(1+2^(1/8))*(1+2^(1/4))*(1+2^(1/2)
1/2+1/4+1/8+1/16+1/32+1/64简便运算＝﹙1／2＋1／4＋1／8＋1／16＋1／32＋1／64＋1
1/(a+1)+2/(1+a^2)+4/(1+a^4)+8/(1+a^8)+16/(1+a^16)-32/(1-a^32
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1),
计算:(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)/（2^32）-1=?
1/2+(-1/4)+(-1/8)+(-1/16)+(-1/32)