从左到右依次求导得：2(x-2)*1+2(y-3)*y'=0,得y'=(2-x)/(y-3) 又因为(y-3)^2=25/(x-2)^2
得y-3=5/(x-2),将y-3带入y'中,可得y'=(2-x)/[5/(x-2)]=-(x-2)^2/5
求(x-2)^2+(y-3)^2=25的隐函数的导数
从左到右依次求导得：2(x-2)*1+2(y-3)*y'=0,得y'=(2-x)/(y-3) 又因为(y-3)^2=25/(x-2)^2
得y-3=5/(x-2),将y-3带入y'中,可得y'=(2-x)/[5/(x-2)]=-(x-2)^2/5