Question

①(x-2)的平方-3(x-2)=4.②a的平方x到平方-2ax+1=ax的平方-x(a不等于0；1）③（a分之x 减1

Answer 1

(x-2)的平方-3(x-2)=4.

(x-2)²-3(x-2)-4=0

(x-2+1)(x-2-4)=0

(x-1)(x-6)=0

x1=1

x2=6

（a分之x 减1）的平方=（b分之x.+1）的平方

(x/a-1)²=(x/b+1)²

(x/a-1)²-(x/b+1)²=0

(x/a-1+x/b+1)(x/a-1-x/b-1)=0

(x/a+x/b)(x/a-x/b-2)=0

x1=0

x/a-x/b-2=0

bx-ax=2ab

(b-a)x=2ab

x2=2ab/(b-a)