3t(t+1)=2t+2
3t(t+1)-2(t+1)=0
(3t-2)(t+1)=0
解得t1=2/3 t2=-1
2(x+5)^2-4(x+5)=0
(x+5)[2(x+5)-4]=0
(x+5)(2x+6)=0
解得x1=-5 x2=-3